Probabiliy formula of mutualy gratuitous events
P(A∩B) = P(A) 10 P(B)
Information :
P(AnB) = Probability occurrence Influenza A virus subtype H5N1 together with occurrence B
P(A) = Probability occurrence A
P(B) = Probability occurrence B
Probabiliy lawsuit of mutualy gratuitous events
On throwing a die at once. A is the incident appearance the die numbers 3 on the showtime die together with B is the incident appearance the die reveal 5 of minute dice. together with then what is the probability of issuing die reveal 3 on the showtime die together with the die reveal 5 on the minute dice?
Resolution :
S = {(1, 1), (1, 2), (1, 3),..., (6, 6)}
n(S) = 36
A = {(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)}
n(A) = 6
P(A) = n(A)/n(S)
P(A) = 6/36
P(A) = 1/6
B = {(1, 5), (2, 5), (3, 5), (4, 5), (5, 5), (5, 6)}
n(B) = 6
P(B) = n(B)/n(S)
P(B) = 6/36
P(B) = 1/6
P(A∩B) = P(A) 10 P(B)
P(A∩B) = (1/6) 10 (1/6)
P(A∩B) = 1/36
P(A∩B) = 0.028
So the probability of issuing die reveal 3 on the showtime die together with the die reveal 5 on minute die is 0.028.
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Reference :
- The mathematics majority of the high schoolhouse shape XI IPA program