Conditional Probability Inwards Math

Two events are called conditional or interdependent events if it occurs or does non come about the A incident volition behavior on the B incident.

Conditional Probability Formula

P(A ∩ B) = P(A/B) . P(B)
P(A ∩ B) = P(B/A) . P(A)

Information :
P (A / B) = Probability occurrence H5N1 alongside status of probability B
P (B / A) = Probability occurrence B alongside status of chance A
P (AnB) = Probability H5N1 in addition to B
P (A) = Probability A
P (B) = Probability B

Conditional Probability Example

From a gear upward of twosome cards, taken ane past times ane twice without return, delight specify the odds of appearing both crimson cards!

Resolution :
First nosotros starting fourth dimension range upward one's hear all that is known inwards the matter, is:
The full disclose of crimson cards inwards the twosome carte du jour is 26, so:
n(A) = 26

Then nosotros detect out how the full disclose of twosome cards, it turns out the carte du jour beridge at that topographic point are 52 entirely, then :
n(S) = 52

Probability for crimson cards appear:
P(A) = n(A)/n(S)
P(A) = 26/52
P(A) = 1/2

Then nosotros await for probability occurrence B later termination A, because the ascendancy is both red, then :
P(B/A) = n(A-1)/n(S-1)
P(B/A) = (26-1)/(52-1)
P(B/A) = 25/51

Probability seem both crimson cards:
P(A∩B) = P(B/A) x P(A)
P(A∩B) = (25/51) x (1/2)
P(A∩B) = 25/102

So the probability of both appearing crimson alongside the status that the carte du jour is non returned is 25/102.

Just this article which I tin portion to you.
I apologize if at that topographic point are incorrect give-and-take on this article
The cease of give-and-take wassalamualaikum wr. wb.

Reference :
  • The mathematics mass of the high schoolhouse course of written report XI IPA program

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