Two events are called conditional or interdependent events if it occurs or does non come about the A incident volition behavior on the B incident.
Conditional Probability Formula
P(A ∩ B) = P(A/B) . P(B)
P(A ∩ B) = P(B/A) . P(A)
Information :
P (A / B) = Probability occurrence H5N1 alongside status of probability B
P (B / A) = Probability occurrence B alongside status of chance A
P (AnB) = Probability H5N1 in addition to B
P (A) = Probability A
P (B) = Probability B
Conditional Probability Example
From a gear upward of twosome cards, taken ane past times ane twice without return, delight specify the odds of appearing both crimson cards!Resolution :
First nosotros starting fourth dimension range upward one's hear all that is known inwards the matter, is:
The full disclose of crimson cards inwards the twosome carte du jour is 26, so:
n(A) = 26
Then nosotros detect out how the full disclose of twosome cards, it turns out the carte du jour beridge at that topographic point are 52 entirely, then :
n(S) = 52
Probability for crimson cards appear:
P(A) = n(A)/n(S)
P(A) = 26/52
P(A) = 1/2
Then nosotros await for probability occurrence B later termination A, because the ascendancy is both red, then :
P(B/A) = n(A-1)/n(S-1)
P(B/A) = (26-1)/(52-1)
P(B/A) = 25/51
Probability seem both crimson cards:
P(A∩B) = P(B/A) x P(A)
P(A∩B) = (25/51) x (1/2)
P(A∩B) = 25/102
So the probability of both appearing crimson alongside the status that the carte du jour is non returned is 25/102.
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The cease of give-and-take wassalamualaikum wr. wb.
Reference :
- The mathematics mass of the high schoolhouse course of written report XI IPA program