Probability of a combination of 2 events mutually unusual are an probability of a combination of 2 events that are non interconnected amongst each other or tin travel called mutually foreign.
Formula of Probability of Influenza A virus subtype H5N1 Combination of Two Events Mutually foreign
P(A∪B) = P(A) + P(B)
Information :
P (A∪B) = Probability of Event Influenza A virus subtype H5N1 or B
P (A) = Probability occurrence A
P (B) = Probability occurrence B
Example of Probability of Influenza A virus subtype H5N1 Combination of Two Events Mutually foreign
In a purse at that topographic point are 10 cards, each numbered consecutively, a carte du jour drawn from the purse at random, for lawsuit A is the upshot that the even-numbered cards are taken too B is the occurrence of an strange numbered prime number card. Look for an A or B conduct a opportunity occurrence!
Resolution:
The inwards a higher house inquiry is a affair of unusual usual occurrence, becouse at that topographic point volition never travel the same members betwixt strange prime number members too fifty-fifty members of the number. For to a greater extent than details run into the flick below:
S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
n(S) = 10
A = {2, 4, 6, 8,10}
n(A)= 5
P(A) = 5/10
B = {3, 5, 7}
n(B) = 3
P(B) = 3/10
P(A∪B) = P(A) + P(B)
P(A∪B) = 5/10 + 3/10
P(A∪B) = (5 + 3)/10
P(A∪B) = 8/10
P(A∪B) = 0.8
So the probability of occurrence of an fifty-fifty release or strange prime number release is 0.8.
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Reference :
- The mathematics mass of the high schoolhouse flat XI IPA program