The Hateful Divergence Formula

For a ready of information x1, x2, x3, ..., xn which has an hateful of  and absolute value of departure per information | x1 -  |, | x2 -  |, | x3 -  |, ..., | xn -  | summed too then divided past times the amount of information too then obtained the hateful departure formulated every bit follows :

The Mean Deviation Formula

RD = 1/n ∑ | xi -  |

Information :
xi = x1, x2, x3, ..., xn
 = Mean of data
n = Amount frequencies of data
∑ = Sigma (number symbol)
RD = Mean departure value

Example :
Determine the hateful departure of 6, 4, 8, 10, 11, 10, 7 !

Answer :
x= 4
x= 6
x= 7
x= 8
x= 10
x= 10
x= 11

n = 7
 = (4 + 6 + 7 + 8 + 10 + 10 + 11) / 7
 = 56 / 7
 = 8
∑ | xi -  |  = | x1 -  | + | x2 -  | + | x3 -  | + | x4 -  | + | x5 -  | + | x6 -  | + | x7 -  |
∑ | xi -  |  = | 4 - 8 | + | 6 - 8 | + | 7 - 8 | + | 8 - 8 | + | 10 - 8 | + | 10 - 8 | + | 11 - 8 |
∑ | xi -  |  = | -4 | + | -2 | + | -1 | + | 0 | + | 2 | + | 2 | + | 3 |
∑ | xi -  |  = 4 + 2 + 1 + 0 + 2 + 2 + 3
∑ | xi -  |  = 14
RD = 1/n ∑ | xi -  |
RD = 1/7 (14)
RD = xiv / 7
RD = 2
So the hateful departure value of 6, 4, 8, 10, 11, 10, 7 is 2

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