For a ready of information x1, x2, x3, ..., xn which has an hateful of x̄ and absolute value of departure per information | x1 - x̄ |, | x2 - x̄ |, | x3 - x̄ |, ..., | xn - x̄ | summed too then divided past times the amount of information too then obtained the hateful departure formulated every bit follows :
The Mean Deviation Formula
RD = 1/n ∑ | xi - x̄ |
Information :
xi = x1, x2, x3, ..., xn
x̄ = Mean of data
n = Amount frequencies of data
∑ = Sigma (number symbol)
RD = Mean departure value
Example :
Determine the hateful departure of 6, 4, 8, 10, 11, 10, 7 !
Answer :
x1 = 4
x2 = 6
x3 = 7
x4 = 8
x5 = 10
x6 = 10
x7 = 11
n = 7
x̄ = (4 + 6 + 7 + 8 + 10 + 10 + 11) / 7
x̄ = 56 / 7
x̄ = 8
∑ | xi - x̄ | = | x1 - x̄ | + | x2 - x̄ | + | x3 - x̄ | + | x4 - x̄ | + | x5 - x̄ | + | x6 - x̄ | + | x7 - x̄ |
∑ | xi - x̄ | = | 4 - 8 | + | 6 - 8 | + | 7 - 8 | + | 8 - 8 | + | 10 - 8 | + | 10 - 8 | + | 11 - 8 |
∑ | xi - x̄ | = | -4 | + | -2 | + | -1 | + | 0 | + | 2 | + | 2 | + | 3 |
∑ | xi - x̄ | = 4 + 2 + 1 + 0 + 2 + 2 + 3
∑ | xi - x̄ | = 14
RD = 1/n ∑ | xi - x̄ |
RD = 1/7 (14)
RD = xiv / 7
RD = 2
So the hateful departure value of 6, 4, 8, 10, 11, 10, 7 is 2
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Referensi :
- Book math grouping sales too accounting bear witness To'ali cast 12